Files
kaniko/integration/cmd.go
T
Priya Wadhwa 6c39f29081 Only return stdout when running commands for integration tests
When running container-diff in integration tests, both stdout and stderr were being returned
and unmarshalled into the container-diff json object. If container-diff
was giving any error messages (such as, if it didn't have permissions to
extract a file), this would fail even if ultimately no
differences between the filesystems existed.

I updated the RunCommands to only return stdout and print stderr if the
command fails.
2018-09-25 10:05:11 -07:00

56 lines
1.5 KiB
Go

/*
Copyright 2018 Google LLC
Licensed under the Apache License, Version 2.0 (the "License");
you may not use this file except in compliance with the License.
You may obtain a copy of the License at
http://www.apache.org/licenses/LICENSE-2.0
Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS" BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
*/
package integration
import (
"bytes"
"fmt"
"os/exec"
"testing"
)
// RunCommandWithoutTest will run cmd and if it fails will output relevant info
// for debugging before returning an error. It can be run outside the context of a test.
func RunCommandWithoutTest(cmd *exec.Cmd) ([]byte, error) {
var stderr bytes.Buffer
cmd.Stderr = &stderr
output, err := cmd.Output()
if err != nil {
fmt.Println(cmd.Args)
fmt.Println(stderr.String())
fmt.Println(string(output))
}
return output, err
}
// RunCommand will run cmd and if it fails will output relevant info for debugging
// before it fails. It must be run within the context of a test t and if the command
// fails, it will the test. Returns the output from the command.
func RunCommand(cmd *exec.Cmd, t *testing.T) []byte {
var stderr bytes.Buffer
cmd.Stderr = &stderr
output, err := cmd.Output()
if err != nil {
t.Log(cmd.Args)
t.Log(stderr.String())
t.Log(string(output))
t.Error(err)
t.FailNow()
}
return output
}